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3t+2/2t-7=0
Domain of the equation: 2t!=0We multiply all the terms by the denominator
t!=0/2
t!=0
t∈R
3t*2t-7*2t+2=0
Wy multiply elements
6t^2-14t+2=0
a = 6; b = -14; c = +2;
Δ = b2-4ac
Δ = -142-4·6·2
Δ = 148
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{148}=\sqrt{4*37}=\sqrt{4}*\sqrt{37}=2\sqrt{37}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{37}}{2*6}=\frac{14-2\sqrt{37}}{12} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{37}}{2*6}=\frac{14+2\sqrt{37}}{12} $
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