3t+3(t-2)=6+2t

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Solution for 3t+3(t-2)=6+2t equation: 



3t+3(t-2)=6+2t

We move all terms to the left:

3t+3(t-2)-(6+2t)=0

We add all the numbers together, and all the variables

3t+3(t-2)-(2t+6)=0

We multiply parentheses

3t+3t-(2t+6)-6=0

We get rid of parentheses

3t+3t-2t-6-6=0

We add all the numbers together, and all the variables

4t-12=0

We move all terms containing t to the left, all other terms to the right

4t=12

t=12/4

t=3

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