3t-18=4(-33/4t

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Solution for 3t-18=4(-33/4t equation: 



3t-18=4(-33/4t

We move all terms to the left:

3t-18-(4(-33/4t)=0



Domain of the equation: 4t)-18!=0

t!=0/1

t!=0

t∈R



We multiply all the terms by the denominator


3t*4t)-18-(4(-33=0

Wy multiply elements

12t^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{0}{24}=0$

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