3t-18=4(-33/4t

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Solution for 3t-18=4(-33/4t equation:



3t-18=4(-33/4t
We move all terms to the left:
3t-18-(4(-33/4t)=0
Domain of the equation: 4t)-18!=0
t!=0/1
t!=0
t∈R
We multiply all the terms by the denominator
3t*4t)-18-(4(-33=0
Wy multiply elements
12t^2=0
a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{0}{24}=0$

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