3t-2(2t-7)=2(3+t)-4

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Solution for 3t-2(2t-7)=2(3+t)-4 equation: 



3t-2(2t-7)=2(3+t)-4

We move all terms to the left:

3t-2(2t-7)-(2(3+t)-4)=0

We add all the numbers together, and all the variables

3t-2(2t-7)-(2(t+3)-4)=0

We multiply parentheses

3t-4t-(2(t+3)-4)+14=0



We calculate terms in parentheses: -(2(t+3)-4), so:

2(t+3)-4

We multiply parentheses

2t+6-4

We add all the numbers together, and all the variables

2t+2

Back to the equation:

-(2t+2)



We add all the numbers together, and all the variables

-1t-(2t+2)+14=0

We get rid of parentheses

-1t-2t-2+14=0

We add all the numbers together, and all the variables

-3t+12=0

We move all terms containing t to the left, all other terms to the right

-3t=-12

t=-12/-3

t=+4

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