3t-5(t+1)=2(2-t)-9

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Solution for 3t-5(t+1)=2(2-t)-9 equation:


Simplifying
3t + -5(t + 1) = 2(2 + -1t) + -9

Reorder the terms:
3t + -5(1 + t) = 2(2 + -1t) + -9
3t + (1 * -5 + t * -5) = 2(2 + -1t) + -9
3t + (-5 + -5t) = 2(2 + -1t) + -9

Reorder the terms:
-5 + 3t + -5t = 2(2 + -1t) + -9

Combine like terms: 3t + -5t = -2t
-5 + -2t = 2(2 + -1t) + -9
-5 + -2t = (2 * 2 + -1t * 2) + -9
-5 + -2t = (4 + -2t) + -9

Reorder the terms:
-5 + -2t = 4 + -9 + -2t

Combine like terms: 4 + -9 = -5
-5 + -2t = -5 + -2t

Add '5' to each side of the equation.
-5 + 5 + -2t = -5 + 5 + -2t

Combine like terms: -5 + 5 = 0
0 + -2t = -5 + 5 + -2t
-2t = -5 + 5 + -2t

Combine like terms: -5 + 5 = 0
-2t = 0 + -2t
-2t = -2t

Add '2t' to each side of the equation.
-2t + 2t = -2t + 2t

Combine like terms: -2t + 2t = 0
0 = -2t + 2t

Combine like terms: -2t + 2t = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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