3t2+21t+30=

Solution for 3t2+21t+30= equation:

3t^2+21t+30=

We move all terms to the left:

3t^2+21t+30-()=0

We add all the numbers together, and all the variables

3t^2+21t=0

a = 3; b = 21; c = 0;
Δ = b2-4ac
Δ = 212-4·3·0
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-21}{2*3}=\frac{-42}{6}
=-7
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+21}{2*3}=\frac{0}{6}
=0
$