3t2+6t=183t2+6t=18

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Solution for 3t2+6t=183t2+6t=18 equation: 



3t^2+6t=183t^2+6t=18

We move all terms to the left:

3t^2+6t-(183t^2+6t)=0

We get rid of parentheses

3t^2-183t^2+6t-6t=0

We add all the numbers together, and all the variables

-180t^2=0

a = -180; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-180)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{0}{-360}=0$

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