3t2=123t2=12t2=4t=

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Solution for 3t2=123t2=12t2=4t= equation: 



3t^2=123t^2=12t^2=4t=

We move all terms to the left:

3t^2-(123t^2)=0

We add all the numbers together, and all the variables

-120t^2=0

a = -120; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-120)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{0}{-240}=0$

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