3t=t2-28

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Solution for 3t=t2-28 equation:



3t=t2-28
We move all terms to the left:
3t-(t2-28)=0
We add all the numbers together, and all the variables
-(+t^2-28)+3t=0
We get rid of parentheses
-t^2+3t+28=0
We add all the numbers together, and all the variables
-1t^2+3t+28=0
a = -1; b = 3; c = +28;
Δ = b2-4ac
Δ = 32-4·(-1)·28
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-11}{2*-1}=\frac{-14}{-2} =+7 $
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+11}{2*-1}=\frac{8}{-2} =-4 $

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