3tanx=1/cosx

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Solution for 3tanx=1/cosx equation:


(4/7)*(b-28) = 0

abs(1*x+0*x^2-1) <= 4*x-1*x^2-3

((1/3)/4)/5 = 0

abs(1*x+0*x^2+2) <= -1*x^2-(6*x)-8

abs(1*x^2+6*x+0) <= 9

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