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3u*5u=16
We move all terms to the left:
3u*5u-(16)=0
Wy multiply elements
15u^2-16=0
a = 15; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·15·(-16)
Δ = 960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{960}=\sqrt{64*15}=\sqrt{64}*\sqrt{15}=8\sqrt{15}$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{15}}{2*15}=\frac{0-8\sqrt{15}}{30} =-\frac{8\sqrt{15}}{30} =-\frac{4\sqrt{15}}{15} $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{15}}{2*15}=\frac{0+8\sqrt{15}}{30} =\frac{8\sqrt{15}}{30} =\frac{4\sqrt{15}}{15} $
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