3u+17=57+u-6

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Solution for 3u+17=57+u-6 equation: 



3u+17=57+u-6

We move all terms to the left:

3u+17-(57+u-6)=0

We add all the numbers together, and all the variables

3u-(u+51)+17=0

We get rid of parentheses

3u-u-51+17=0

We add all the numbers together, and all the variables

2u-34=0

We move all terms containing u to the left, all other terms to the right

2u=34

u=34/2

u=17

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