3u+2-2(-4u-1)=2(u-4)

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Solution for 3u+2-2(-4u-1)=2(u-4) equation: 



3u+2-2(-4u-1)=2(u-4)

We move all terms to the left:

3u+2-2(-4u-1)-(2(u-4))=0

We multiply parentheses

3u+8u-(2(u-4))+2+2=0



We calculate terms in parentheses: -(2(u-4)), so:

2(u-4)

We multiply parentheses

2u-8

Back to the equation:

-(2u-8)



We add all the numbers together, and all the variables

11u-(2u-8)+4=0

We get rid of parentheses

11u-2u+8+4=0

We add all the numbers together, and all the variables

9u+12=0

We move all terms containing u to the left, all other terms to the right

9u=-12

u=-12/9

u=-1+1/3

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