3u+28=8u-12

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Solution for 3u+28=8u-12 equation: 



3u+28=8u-12

We move all terms to the left:

3u+28-(8u-12)=0

We get rid of parentheses

3u-8u+12+28=0

We add all the numbers together, and all the variables

-5u+40=0

We move all terms containing u to the left, all other terms to the right

-5u=-40

u=-40/-5

u=+8

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