3u+3-2(-7u-3)=3(u-3)

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Solution for 3u+3-2(-7u-3)=3(u-3) equation: 



3u+3-2(-7u-3)=3(u-3)

We move all terms to the left:

3u+3-2(-7u-3)-(3(u-3))=0

We multiply parentheses

3u+14u-(3(u-3))+6+3=0



We calculate terms in parentheses: -(3(u-3)), so:

3(u-3)

We multiply parentheses

3u-9

Back to the equation:

-(3u-9)



We add all the numbers together, and all the variables

17u-(3u-9)+9=0

We get rid of parentheses

17u-3u+9+9=0

We add all the numbers together, and all the variables

14u+18=0

We move all terms containing u to the left, all other terms to the right

14u=-18

u=-18/14

u=-1+2/7

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