3u+32=8(u-1)

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Solution for 3u+32=8(u-1) equation: 



3u+32=8(u-1)

We move all terms to the left:

3u+32-(8(u-1))=0



We calculate terms in parentheses: -(8(u-1)), so:

8(u-1)

We multiply parentheses

8u-8

Back to the equation:

-(8u-8)



We get rid of parentheses

3u-8u+8+32=0

We add all the numbers together, and all the variables

-5u+40=0

We move all terms containing u to the left, all other terms to the right

-5u=-40

u=-40/-5

u=+8

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