3u+4-2(-3u-1)=3(u-1)

Solution for 3u+4-2(-3u-1)=3(u-1) equation:

3u+4-2(-3u-1)=3(u-1)

We move all terms to the left:

3u+4-2(-3u-1)-(3(u-1))=0

We multiply parentheses

3u+6u-(3(u-1))+2+4=0


We calculate terms in parentheses: -(3(u-1)), so:

3(u-1)

We multiply parentheses

3u-3

Back to the equation:

-(3u-3)


We add all the numbers together, and all the variables

9u-(3u-3)+6=0

We get rid of parentheses

9u-3u+3+6=0

We add all the numbers together, and all the variables

6u+9=0

We move all terms containing u to the left, all other terms to the right

6u=-9

u=-9/6

u=-1+1/2