3u+4-5(-2u-1)=3(u-2)

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Solution for 3u+4-5(-2u-1)=3(u-2) equation: 



3u+4-5(-2u-1)=3(u-2)

We move all terms to the left:

3u+4-5(-2u-1)-(3(u-2))=0

We multiply parentheses

3u+10u-(3(u-2))+5+4=0



We calculate terms in parentheses: -(3(u-2)), so:

3(u-2)

We multiply parentheses

3u-6

Back to the equation:

-(3u-6)



We add all the numbers together, and all the variables

13u-(3u-6)+9=0

We get rid of parentheses

13u-3u+6+9=0

We add all the numbers together, and all the variables

10u+15=0

We move all terms containing u to the left, all other terms to the right

10u=-15

u=-15/10

u=-1+1/2

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