3u+5-4(-3u-2)=5(u-1)

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Solution for 3u+5-4(-3u-2)=5(u-1) equation: 



3u+5-4(-3u-2)=5(u-1)

We move all terms to the left:

3u+5-4(-3u-2)-(5(u-1))=0

We multiply parentheses

3u+12u-(5(u-1))+8+5=0



We calculate terms in parentheses: -(5(u-1)), so:

5(u-1)

We multiply parentheses

5u-5

Back to the equation:

-(5u-5)



We add all the numbers together, and all the variables

15u-(5u-5)+13=0

We get rid of parentheses

15u-5u+5+13=0

We add all the numbers together, and all the variables

10u+18=0

We move all terms containing u to the left, all other terms to the right

10u=-18

u=-18/10

u=-1+4/5

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