3u-1=3(2-u)-1

Solution for 3u-1=3(2-u)-1 equation:

3u-1=3(2-u)-1

We move all terms to the left:

3u-1-(3(2-u)-1)=0

We add all the numbers together, and all the variables

3u-(3(-1u+2)-1)-1=0


We calculate terms in parentheses: -(3(-1u+2)-1), so:

3(-1u+2)-1

We multiply parentheses

-3u+6-1

We add all the numbers together, and all the variables

-3u+5

Back to the equation:

-(-3u+5)


We get rid of parentheses

3u+3u-5-1=0

We add all the numbers together, and all the variables

6u-6=0

We move all terms containing u to the left, all other terms to the right

6u=6

u=6/6

u=1