3u-2=3(4-u)-2

Solution for 3u-2=3(4-u)-2 equation:

3u-2=3(4-u)-2

We move all terms to the left:

3u-2-(3(4-u)-2)=0

We add all the numbers together, and all the variables

3u-(3(-1u+4)-2)-2=0


We calculate terms in parentheses: -(3(-1u+4)-2), so:

3(-1u+4)-2

We multiply parentheses

-3u+12-2

We add all the numbers together, and all the variables

-3u+10

Back to the equation:

-(-3u+10)


We get rid of parentheses

3u+3u-10-2=0

We add all the numbers together, and all the variables

6u-12=0

We move all terms containing u to the left, all other terms to the right

6u=12

u=12/6

u=2