3u-3+6(2u+1)=-3(u+2)

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Solution for 3u-3+6(2u+1)=-3(u+2) equation: 



3u-3+6(2u+1)=-3(u+2)

We move all terms to the left:

3u-3+6(2u+1)-(-3(u+2))=0

We multiply parentheses

3u+12u-(-3(u+2))+6-3=0



We calculate terms in parentheses: -(-3(u+2)), so:

-3(u+2)

We multiply parentheses

-3u-6

Back to the equation:

-(-3u-6)



We add all the numbers together, and all the variables

15u-(-3u-6)+3=0

We get rid of parentheses

15u+3u+6+3=0

We add all the numbers together, and all the variables

18u+9=0

We move all terms containing u to the left, all other terms to the right

18u=-9

u=-9/18

u=-1/2

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