3u-4+2(3u+1)=-3(u+4)

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Solution for 3u-4+2(3u+1)=-3(u+4) equation: 



3u-4+2(3u+1)=-3(u+4)

We move all terms to the left:

3u-4+2(3u+1)-(-3(u+4))=0

We multiply parentheses

3u+6u-(-3(u+4))+2-4=0



We calculate terms in parentheses: -(-3(u+4)), so:

-3(u+4)

We multiply parentheses

-3u-12

Back to the equation:

-(-3u-12)



We add all the numbers together, and all the variables

9u-(-3u-12)-2=0

We get rid of parentheses

9u+3u+12-2=0

We add all the numbers together, and all the variables

12u+10=0

We move all terms containing u to the left, all other terms to the right

12u=-10

u=-10/12

u=-5/6

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