3u-4+2(3u+2)=-6(u+2)

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Solution for 3u-4+2(3u+2)=-6(u+2) equation: 



3u-4+2(3u+2)=-6(u+2)

We move all terms to the left:

3u-4+2(3u+2)-(-6(u+2))=0

We multiply parentheses

3u+6u-(-6(u+2))+4-4=0



We calculate terms in parentheses: -(-6(u+2)), so:

-6(u+2)

We multiply parentheses

-6u-12

Back to the equation:

-(-6u-12)



We add all the numbers together, and all the variables

9u-(-6u-12)=0

We get rid of parentheses

9u+6u+12=0

We add all the numbers together, and all the variables

15u+12=0

We move all terms containing u to the left, all other terms to the right

15u=-12

u=-12/15

u=-4/5

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