3u-41+3u=4u+12

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Solution for 3u-41+3u=4u+12 equation: 



3u-41+3u=4u+12

We move all terms to the left:

3u-41+3u-(4u+12)=0

We add all the numbers together, and all the variables

6u-(4u+12)-41=0

We get rid of parentheses

6u-4u-12-41=0

We add all the numbers together, and all the variables

2u-53=0

We move all terms containing u to the left, all other terms to the right

2u=53

u=53/2

u=26+1/2

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