3u-5+2(5u+1)=-3(u+7)

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Solution for 3u-5+2(5u+1)=-3(u+7) equation: 



3u-5+2(5u+1)=-3(u+7)

We move all terms to the left:

3u-5+2(5u+1)-(-3(u+7))=0

We multiply parentheses

3u+10u-(-3(u+7))+2-5=0



We calculate terms in parentheses: -(-3(u+7)), so:

-3(u+7)

We multiply parentheses

-3u-21

Back to the equation:

-(-3u-21)



We add all the numbers together, and all the variables

13u-(-3u-21)-3=0

We get rid of parentheses

13u+3u+21-3=0

We add all the numbers together, and all the variables

16u+18=0

We move all terms containing u to the left, all other terms to the right

16u=-18

u=-18/16

u=-1+1/8

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