3u-5+3(3u+3)=-6(u+1)

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Solution for 3u-5+3(3u+3)=-6(u+1) equation: 



3u-5+3(3u+3)=-6(u+1)

We move all terms to the left:

3u-5+3(3u+3)-(-6(u+1))=0

We multiply parentheses

3u+9u-(-6(u+1))+9-5=0



We calculate terms in parentheses: -(-6(u+1)), so:

-6(u+1)

We multiply parentheses

-6u-6

Back to the equation:

-(-6u-6)



We add all the numbers together, and all the variables

12u-(-6u-6)+4=0

We get rid of parentheses

12u+6u+6+4=0

We add all the numbers together, and all the variables

18u+10=0

We move all terms containing u to the left, all other terms to the right

18u=-10

u=-10/18

u=-5/9

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