3u-6+2(2u+5)=-2(u+4)

Solution for 3u-6+2(2u+5)=-2(u+4) equation:

3u-6+2(2u+5)=-2(u+4)

We move all terms to the left:

3u-6+2(2u+5)-(-2(u+4))=0

We multiply parentheses

3u+4u-(-2(u+4))+10-6=0


We calculate terms in parentheses: -(-2(u+4)), so:

-2(u+4)

We multiply parentheses

-2u-8

Back to the equation:

-(-2u-8)


We add all the numbers together, and all the variables

7u-(-2u-8)+4=0

We get rid of parentheses

7u+2u+8+4=0

We add all the numbers together, and all the variables

9u+12=0

We move all terms containing u to the left, all other terms to the right

9u=-12

u=-12/9

u=-1+1/3