3u-6+5(2u+4)=-2(u+2)

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Solution for 3u-6+5(2u+4)=-2(u+2) equation: 



3u-6+5(2u+4)=-2(u+2)

We move all terms to the left:

3u-6+5(2u+4)-(-2(u+2))=0

We multiply parentheses

3u+10u-(-2(u+2))+20-6=0



We calculate terms in parentheses: -(-2(u+2)), so:

-2(u+2)

We multiply parentheses

-2u-4

Back to the equation:

-(-2u-4)



We add all the numbers together, and all the variables

13u-(-2u-4)+14=0

We get rid of parentheses

13u+2u+4+14=0

We add all the numbers together, and all the variables

15u+18=0

We move all terms containing u to the left, all other terms to the right

15u=-18

u=-18/15

u=-1+1/5

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