3u-7+4(2u+2)=-3(u+5)

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Solution for 3u-7+4(2u+2)=-3(u+5) equation: 



3u-7+4(2u+2)=-3(u+5)

We move all terms to the left:

3u-7+4(2u+2)-(-3(u+5))=0

We multiply parentheses

3u+8u-(-3(u+5))+8-7=0



We calculate terms in parentheses: -(-3(u+5)), so:

-3(u+5)

We multiply parentheses

-3u-15

Back to the equation:

-(-3u-15)



We add all the numbers together, and all the variables

11u-(-3u-15)+1=0

We get rid of parentheses

11u+3u+15+1=0

We add all the numbers together, and all the variables

14u+16=0

We move all terms containing u to the left, all other terms to the right

14u=-16

u=-16/14

u=-1+1/7

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