3u-9+2(4u+2)=-5(u+3)

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Solution for 3u-9+2(4u+2)=-5(u+3) equation: 



3u-9+2(4u+2)=-5(u+3)

We move all terms to the left:

3u-9+2(4u+2)-(-5(u+3))=0

We multiply parentheses

3u+8u-(-5(u+3))+4-9=0



We calculate terms in parentheses: -(-5(u+3)), so:

-5(u+3)

We multiply parentheses

-5u-15

Back to the equation:

-(-5u-15)



We add all the numbers together, and all the variables

11u-(-5u-15)-5=0

We get rid of parentheses

11u+5u+15-5=0

We add all the numbers together, and all the variables

16u+10=0

We move all terms containing u to the left, all other terms to the right

16u=-10

u=-10/16

u=-5/8

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