3u-u=2(u-1)+5

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Solution for 3u-u=2(u-1)+5 equation: 



3u-u=2(u-1)+5

We move all terms to the left:

3u-u-(2(u-1)+5)=0

We add all the numbers together, and all the variables

2u-(2(u-1)+5)=0



We calculate terms in parentheses: -(2(u-1)+5), so:

2(u-1)+5

We multiply parentheses

2u-2+5

We add all the numbers together, and all the variables

2u+3

Back to the equation:

-(2u+3)



We get rid of parentheses

2u-2u-3=0

We add all the numbers together, and all the variables

-3!=0

There is no solution for this equation

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