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3v*3v=v+10
We move all terms to the left:
3v*3v-(v+10)=0
Wy multiply elements
9v^2-(v+10)=0
We get rid of parentheses
9v^2-v-10=0
We add all the numbers together, and all the variables
9v^2-1v-10=0
a = 9; b = -1; c = -10;
Δ = b2-4ac
Δ = -12-4·9·(-10)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-19}{2*9}=\frac{-18}{18} =-1 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+19}{2*9}=\frac{20}{18} =1+1/9 $
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