3v+1-2(-3v-3)=3(v+1)

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Solution for 3v+1-2(-3v-3)=3(v+1) equation: 



3v+1-2(-3v-3)=3(v+1)

We move all terms to the left:

3v+1-2(-3v-3)-(3(v+1))=0

We multiply parentheses

3v+6v-(3(v+1))+6+1=0



We calculate terms in parentheses: -(3(v+1)), so:

3(v+1)

We multiply parentheses

3v+3

Back to the equation:

-(3v+3)



We add all the numbers together, and all the variables

9v-(3v+3)+7=0

We get rid of parentheses

9v-3v-3+7=0

We add all the numbers together, and all the variables

6v+4=0

We move all terms containing v to the left, all other terms to the right

6v=-4

v=-4/6

v=-2/3

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