3v+1-2(-3v-3)=3(v-1)

Solution for 3v+1-2(-3v-3)=3(v-1) equation:

3v+1-2(-3v-3)=3(v-1)

We move all terms to the left:

3v+1-2(-3v-3)-(3(v-1))=0

We multiply parentheses

3v+6v-(3(v-1))+6+1=0


We calculate terms in parentheses: -(3(v-1)), so:

3(v-1)

We multiply parentheses

3v-3

Back to the equation:

-(3v-3)


We add all the numbers together, and all the variables

9v-(3v-3)+7=0

We get rid of parentheses

9v-3v+3+7=0

We add all the numbers together, and all the variables

6v+10=0

We move all terms containing v to the left, all other terms to the right

6v=-10

v=-10/6

v=-1+2/3