3v+3(2v-6)=7v+4(4v+3)

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Solution for 3v+3(2v-6)=7v+4(4v+3) equation: 



3v+3(2v-6)=7v+4(4v+3)

We move all terms to the left:

3v+3(2v-6)-(7v+4(4v+3))=0

We multiply parentheses

3v+6v-(7v+4(4v+3))-18=0



We calculate terms in parentheses: -(7v+4(4v+3)), so:

7v+4(4v+3)

We multiply parentheses

7v+16v+12

We add all the numbers together, and all the variables

23v+12

Back to the equation:

-(23v+12)



We add all the numbers together, and all the variables

9v-(23v+12)-18=0

We get rid of parentheses

9v-23v-12-18=0

We add all the numbers together, and all the variables

-14v-30=0

We move all terms containing v to the left, all other terms to the right

-14v=30

v=30/-14

v=-2+1/7

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