3v+4-2(-4v-1)=3(v-4)

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Solution for 3v+4-2(-4v-1)=3(v-4) equation: 



3v+4-2(-4v-1)=3(v-4)

We move all terms to the left:

3v+4-2(-4v-1)-(3(v-4))=0

We multiply parentheses

3v+8v-(3(v-4))+2+4=0



We calculate terms in parentheses: -(3(v-4)), so:

3(v-4)

We multiply parentheses

3v-12

Back to the equation:

-(3v-12)



We add all the numbers together, and all the variables

11v-(3v-12)+6=0

We get rid of parentheses

11v-3v+12+6=0

We add all the numbers together, and all the variables

8v+18=0

We move all terms containing v to the left, all other terms to the right

8v=-18

v=-18/8

v=-2+1/4

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