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3v+5v+9=2(4v-6)
We move all terms to the left:
3v+5v+9-(2(4v-6))=0
We add all the numbers together, and all the variables
8v-(2(4v-6))+9=0
We calculate terms in parentheses: -(2(4v-6)), so:We get rid of parentheses
2(4v-6)
We multiply parentheses
8v-12
Back to the equation:
-(8v-12)
8v-8v+12+9=0
We add all the numbers together, and all the variables
21!=0
There is no solution for this equation
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