3v-1+2(6v+5)=-3(v+2)

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Solution for 3v-1+2(6v+5)=-3(v+2) equation: 



3v-1+2(6v+5)=-3(v+2)

We move all terms to the left:

3v-1+2(6v+5)-(-3(v+2))=0

We multiply parentheses

3v+12v-(-3(v+2))+10-1=0



We calculate terms in parentheses: -(-3(v+2)), so:

-3(v+2)

We multiply parentheses

-3v-6

Back to the equation:

-(-3v-6)



We add all the numbers together, and all the variables

15v-(-3v-6)+9=0

We get rid of parentheses

15v+3v+6+9=0

We add all the numbers together, and all the variables

18v+15=0

We move all terms containing v to the left, all other terms to the right

18v=-15

v=-15/18

v=-5/6

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