3v-11(-v+7)=7(6+6v)-11v

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Solution for 3v-11(-v+7)=7(6+6v)-11v equation: 



3v-11(-v+7)=7(6+6v)-11v

We move all terms to the left:

3v-11(-v+7)-(7(6+6v)-11v)=0

We add all the numbers together, and all the variables

3v-11(-1v+7)-(7(6v+6)-11v)=0

We multiply parentheses

3v+11v-(7(6v+6)-11v)-77=0



We calculate terms in parentheses: -(7(6v+6)-11v), so:

7(6v+6)-11v

We add all the numbers together, and all the variables

-11v+7(6v+6)

We multiply parentheses

-11v+42v+42

We add all the numbers together, and all the variables

31v+42

Back to the equation:

-(31v+42)



We add all the numbers together, and all the variables

14v-(31v+42)-77=0

We get rid of parentheses

14v-31v-42-77=0

We add all the numbers together, and all the variables

-17v-119=0

We move all terms containing v to the left, all other terms to the right

-17v=119

v=119/-17

v=-7

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