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3v-11=2(5+5v)
We move all terms to the left:
3v-11-(2(5+5v))=0
We add all the numbers together, and all the variables
3v-(2(5v+5))-11=0
We calculate terms in parentheses: -(2(5v+5)), so:We get rid of parentheses
2(5v+5)
We multiply parentheses
10v+10
Back to the equation:
-(10v+10)
3v-10v-10-11=0
We add all the numbers together, and all the variables
-7v-21=0
We move all terms containing v to the left, all other terms to the right
-7v=21
v=21/-7
v=-3
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