3v-3+2(3v+5)=-5(v+1)

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Solution for 3v-3+2(3v+5)=-5(v+1) equation: 



3v-3+2(3v+5)=-5(v+1)

We move all terms to the left:

3v-3+2(3v+5)-(-5(v+1))=0

We multiply parentheses

3v+6v-(-5(v+1))+10-3=0



We calculate terms in parentheses: -(-5(v+1)), so:

-5(v+1)

We multiply parentheses

-5v-5

Back to the equation:

-(-5v-5)



We add all the numbers together, and all the variables

9v-(-5v-5)+7=0

We get rid of parentheses

9v+5v+5+7=0

We add all the numbers together, and all the variables

14v+12=0

We move all terms containing v to the left, all other terms to the right

14v=-12

v=-12/14

v=-6/7

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