3v-4+2(3v+1)=-5(v+4)

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Solution for 3v-4+2(3v+1)=-5(v+4) equation: 



3v-4+2(3v+1)=-5(v+4)

We move all terms to the left:

3v-4+2(3v+1)-(-5(v+4))=0

We multiply parentheses

3v+6v-(-5(v+4))+2-4=0



We calculate terms in parentheses: -(-5(v+4)), so:

-5(v+4)

We multiply parentheses

-5v-20

Back to the equation:

-(-5v-20)



We add all the numbers together, and all the variables

9v-(-5v-20)-2=0

We get rid of parentheses

9v+5v+20-2=0

We add all the numbers together, and all the variables

14v+18=0

We move all terms containing v to the left, all other terms to the right

14v=-18

v=-18/14

v=-1+2/7

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