3v-7+3(3v+5)=-2(v+4)

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Solution for 3v-7+3(3v+5)=-2(v+4) equation: 



3v-7+3(3v+5)=-2(v+4)

We move all terms to the left:

3v-7+3(3v+5)-(-2(v+4))=0

We multiply parentheses

3v+9v-(-2(v+4))+15-7=0



We calculate terms in parentheses: -(-2(v+4)), so:

-2(v+4)

We multiply parentheses

-2v-8

Back to the equation:

-(-2v-8)



We add all the numbers together, and all the variables

12v-(-2v-8)+8=0

We get rid of parentheses

12v+2v+8+8=0

We add all the numbers together, and all the variables

14v+16=0

We move all terms containing v to the left, all other terms to the right

14v=-16

v=-16/14

v=-1+1/7

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