3v-9+2(4v+5)=-7(v+1)

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Solution for 3v-9+2(4v+5)=-7(v+1) equation: 



3v-9+2(4v+5)=-7(v+1)

We move all terms to the left:

3v-9+2(4v+5)-(-7(v+1))=0

We multiply parentheses

3v+8v-(-7(v+1))+10-9=0



We calculate terms in parentheses: -(-7(v+1)), so:

-7(v+1)

We multiply parentheses

-7v-7

Back to the equation:

-(-7v-7)



We add all the numbers together, and all the variables

11v-(-7v-7)+1=0

We get rid of parentheses

11v+7v+7+1=0

We add all the numbers together, and all the variables

18v+8=0

We move all terms containing v to the left, all other terms to the right

18v=-8

v=-8/18

v=-4/9

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