3v2+26v+49=0

Solution for 3v2+26v+49=0 equation:

3v^2+26v+49=0

a = 3; b = 26; c = +49;
Δ = b2-4ac
Δ = 262-4·3·49
Δ = 88
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{88}=\sqrt{4*22}=\sqrt{4}*\sqrt{22}=2\sqrt{22}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-2\sqrt{22}}{2*3}=\frac{-26-2\sqrt{22}}{6}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+2\sqrt{22}}{2*3}=\frac{-26+2\sqrt{22}}{6}
$