3v2+36v+49=8v

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Solution for 3v2+36v+49=8v equation:



3v^2+36v+49=8v
We move all terms to the left:
3v^2+36v+49-(8v)=0
We add all the numbers together, and all the variables
3v^2+28v+49=0
a = 3; b = 28; c = +49;
Δ = b2-4ac
Δ = 282-4·3·49
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-14}{2*3}=\frac{-42}{6} =-7 $
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+14}{2*3}=\frac{-14}{6} =-2+1/3 $

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