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3v^2-9v-54=0
a = 3; b = -9; c = -54;
Δ = b2-4ac
Δ = -92-4·3·(-54)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-27}{2*3}=\frac{-18}{6} =-3 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+27}{2*3}=\frac{36}{6} =6 $
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