3w(w+1)=-(w+2)

Solution for 3w(w+1)=-(w+2) equation:

3w(w+1)=-(w+2)

We move all terms to the left:

3w(w+1)-(-(w+2))=0

We multiply parentheses

3w^2+3w-(-(w+2))=0


We calculate terms in parentheses: -(-(w+2)), so:

-(w+2)

We get rid of parentheses

-w-2

We add all the numbers together, and all the variables

-1w-2

Back to the equation:

-(-1w-2)


We get rid of parentheses

3w^2+3w+1w+2=0

We add all the numbers together, and all the variables

3w^2+4w+2=0

a = 3; b = 4; c = +2;
Δ = b2-4ac
Δ = 42-4·3·2
Δ = -8
Delta is less than zero, so there is no solution for the equation