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3w*w=40
We move all terms to the left:
3w*w-(40)=0
Wy multiply elements
3w^2-40=0
a = 3; b = 0; c = -40;
Δ = b2-4ac
Δ = 02-4·3·(-40)
Δ = 480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{480}=\sqrt{16*30}=\sqrt{16}*\sqrt{30}=4\sqrt{30}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{30}}{2*3}=\frac{0-4\sqrt{30}}{6} =-\frac{4\sqrt{30}}{6} =-\frac{2\sqrt{30}}{3} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{30}}{2*3}=\frac{0+4\sqrt{30}}{6} =\frac{4\sqrt{30}}{6} =\frac{2\sqrt{30}}{3} $
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